強連結成分分解。深さ優先探索を二回行う

計算量

$\mathcal{O}(V+E)$

テンプレート

#include <cassert>
#include <algorithm>
#include <iostream>
#include <vector>

using namespace std;

struct Edge {
  int from, to, cost;
  Edge() {}
  Edge(int f, int t) : cost(1), from(f), to(t) {}
  Edge(int f, int t, int c) : from(f), to(t), cost(c) {}
  friend bool operator < (const Edge& lhs, const Edge& rhs) { return lhs.cost < rhs.cost; };
  friend bool operator > (const Edge& lhs, const Edge& rhs) { return rhs < lhs; };
  friend bool operator <= (const Edge& lhs, const Edge& rhs) { return !(lhs > rhs); };
  friend bool operator >= (const Edge& lhs, const Edge& rhs) { return !(lhs < rhs); };
};

typedef vector<vector<Edge>> Graph;

struct stronglyConnectedComponents {
  const int V;
  Graph g, rg;
  vector<bool> visit;
  vector<int> comp, order;
  vector<vector<int>> components;

  stronglyConnectedComponents(const Graph &g) : V(g.size()), g(g), rg(V), visit(V, false), comp(V, -1) {
    // 辺の向きを逆にしたグラフを構築
    for (int v = 0; v < V; ++v) {
      for (auto &e : g[v]) { 
        rg[e.to].emplace_back(e.to, e.from);
      }
    }
  }

  // 同じ強連結成分に属していればtrueを返す
  bool same(int s, int t) { 
    assert(comp[s] != -1 && comp[t] != -1);
    return comp[s] == comp[t];
  }

  void dfs(int sv) { 
    if (visit[sv]) return;
    visit[sv] = true;
    for (auto &e : g[sv]) { 
      dfs(e.to);
    }
    order.push_back(sv);
  }

  void rdfs(int sv, int cnt) { 
    if (comp[sv] != -1) return;
    comp[sv] = cnt;

    if (components.size() <= cnt) { 
      vector<int> v;
      components.push_back(v);
    }
    components[cnt].push_back(sv);

    for (auto &e : rg[sv]) { 
      rdfs(e.to, cnt);
    }
  }

  void build() {
    for(int i = 0; i < V; i++) { dfs(i); } 
    assert(order.size() == V);
    reverse(order.begin(), order.end()); // dfsでつけた番号を逆順にする
    int cnt = 0; // 強連結成分毎のid
    for (int v : order) { 
      if (comp[v] != -1) continue;
      rdfs(v, cnt);
      // 強連結成分の頂点をループの順に並び替え
      if (components[cnt].size() > 1) {
        reverse(components[cnt].begin()+1, components[cnt].end());
      }
      ++cnt;
    }
  }
};

int main() {
  int V, E;
  cin >> V >> E;
  Graph graph(V);
  for (int i = 0; i < E; ++i) {
    int x, y;
    cin >> x >> y;
    graph[x].emplace_back(x, y);
  }
  stronglyConnectedComponents scc(graph);
  scc.build();
  int Q;
  cin >> Q;
  for (int i = 0; i < Q; ++i) { 
    int u, v;
    cin >> u >> v;
    if (scc.same(u, v)) { cout << "1" << endl; }
    else { cout << "0" << endl; }
  }
}

利用例

img
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_3_C

% cat 1.in
5 6
0 1
1 0
1 2
2 4
4 3
3 2
4
0 1
0 3
2 3
3 4
% g++ -std=gnu++1y -O2 strongly-connected-components.cpp -o run
% ./run < 1.in
1
0
1
1

参考